Question

Tìm \(n\in N\) để:

\(\left(n^2+5\right)⋮\left(n+1\right)\)

Answer 1

\(n^2+5=n^2+n-n+5=n\left(n+1\right)-n+5=n\left(n+1\right)-\left(n-5\right)\) chia hết cho n + 1

<=> n - 5 = n + 1 - 6 chia hết cho n + 1

<=> 6 chia hết cho n + 1

<=> n + 1 \(\in\) Ư(6) = {1; 2; 3; 6}

<=> n \(\in\) {0; 1; 2; 5}

Answer 2

n=1 ,2,3,6 nha bn

chuc bn hoc tot

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