Question

Tìm n để : n+4chia hết cho n+1

Answer 1

THEO ĐỀ BÀI, TA CÓ:

\(\left(n+4\right)⋮\left(n+1\right)\Rightarrow\left[\left(n+1\right)+3\right]⋮\left(n+1\right)\)

\(\Rightarrow3⋮\left(n+1\right)\)

\(\Rightarrow\left(n+1\right)\in\left\{1;-1;3;-3\right\}\)

\(\Rightarrow n\in\left\{0;-2;2;-4\right\}\)

Answer 2

( n + 4 ) chia hết ( n+ 1)

=>[(n+1)+3] chia hết ( n +1 )

=>3 chia hết ( n+1)

=> ( n + 1 ) \(\in\) { \(\pm\)1 ; \(\pm\)3 }

ta c

n+1 -3 3 1 -1 n -4 2 0 -2