a) Đặt \(A=-3-\left|a+2\right|\)
Ta có: \(-\left|a+2\right|\le0\)
\(\Rightarrow A=-3-\left|a+2\right|\le-3\)
Vậy \(MAX_A=-3\) khi a = -2
b) Đặt \(B=-7+\left(x-1\right)^2\)
Ta có: \(\left(x-1\right)^2\ge0\)
\(\Rightarrow B=-7+\left(x-1\right)^2\ge-7\)
Vậy \(MIN_B=-7\) khi x = 1