\(y'=-\frac{3}{x^4}+\frac{1}{x^2}=0\Leftrightarrow\frac{1}{x^2}\left(1-\frac{3}{x^2}\right)=0\Rightarrow x=\sqrt{3}\)
\(y'< 0\) khi \(0< x< \sqrt{3}\) ; \(y'>0\) khi \(x>3\)
Từ BBT ta thấy \(y_{min}=y\left(\sqrt{3}\right)=\frac{1}{3\sqrt{3}}-\frac{1}{\sqrt{3}}=-\frac{2\sqrt{3}}{9}\)