Ta có:
\(A=\dfrac{5n-19}{2n-7}\)
\(A_{MIN}\Leftrightarrow2n-7_{MAX}\)
\(A_{MIN}\Rightarrow A\in Z^-\)
\(\Leftrightarrow2n-7=-1\Rightarrow2n=-6\Rightarrow n=-3\)
Thay -3 vào n ta có:
\(A=\dfrac{5.3-19}{5.2-7}=\dfrac{-4}{3}\)
\(A=\dfrac{-4}{3}\Leftrightarrow n=-3\)