Ta có: \(-1\le\sin x\le1\)
\(\Leftrightarrow-2\le2\sin x\le2\)
\(\Leftrightarrow1\le2\sin x+3\le5\)
\(\Leftrightarrow1\le\sqrt{2\sin x+3}\le\sqrt{5}\)
\(\Leftrightarrow1\le y\le5\)
Vậy: \(MIN_y=1\) khi \(\sin x=-1\)
\(M AX_y=\sqrt{5}\) khi \(\sin x=1\)