Question

Tim gia tri cua x de M(x)=-9

M(x)= \(-4x^2-2x+7\)

Answer 1

M(x) = -4x^2 - 2x + 7 = -9

<=> -4x^2 - 2x + 16= 0

<=> x = \(\dfrac{-1\pm\sqrt{65}}{4}\)

Answer 2

M(x) = -4x^2 - 2x + 7 = -9

=> -4x^2 - 2x + 16= 0

=> x = \(\dfrac{-1\text{±}\sqrt{65}}{4}\)

Answer 3

M(x) = -4x² - 2x + 7 = -9

=> -4x² - 2x + 16= 0

=> x = \(\dfrac{\text{−1±√65}}{4}\)