Đặt ƯC ( 2n-1 ; 3n+1 ) = d(n>0)
=>\(\left\{{}\begin{matrix}2n-1⋮d\\3n+1⋮d\end{matrix}\right.\)(n>0)
<=> (2n-1) - (3n+1)\(⋮\)d
<=>3(2n-1)-2(3n+1)\(⋮\)d
<=>(6n-3)-(6n+2)\(⋮d\)
<=>6n-3-6n-2\(⋮\)d
<=>-5\(⋮\)d
=>d\(\in\) ƯC(5) \(\in\){\(\pm1;\pm5\)}
Vậy ƯC ( 2n-1;3n+1) = {\(\pm1;\pm5\)}