ta có:
\(\dfrac{a}{5}-\dfrac{2}{b}=\dfrac{2}{15}\)
=>\(\dfrac{a.b-2}{5.b}=\dfrac{2}{15}\)
=>(a.b-2).15=b.5.2
a.b.15-30=b.10
a.b.5-30=0
a.b.5=30
a.b=30:5
a.b=6
ta có bảng sau:
a
|
1 |
2 |
3 |
6 |
b
|
6 |
3 |
2 |
1 |