a) \(1,25-\left|0,5-x\right|=0\)
\(\Rightarrow\left|0,5-x\right|=1,25\)
\(\Rightarrow\begin{cases}0,5-x=1,25\\0,5-x=-1,25\end{cases}\)
\(\Rightarrow\begin{cases}x=-0,75\\x=1,75\end{cases}\)
Vậy \(x=\begin{cases}-0,75\\1,75\end{cases}\)
a) \(1,25-\left|0,5-x\right|=0\)
\(\Leftrightarrow\left|0,5-x\right|=1,25\)
+)TH1: x =< 0,5 thì pt trở thành:
0,5-x=1,25 <=> x=-0,75 (tm)
+)TH2: x>0,5 thì pt trở thành:
x-0,5=1,25 <=> x=1,75 (tm)
Vậy x={-0,75;1,75}
b) \(\left|2x\right|-\left|-3,5\right|=\left|-6,5\right|\)
\(\Leftrightarrow\left|2x\right|=10\)
+)Th1: x>= 0 thì pt trở thành:
2x=10 <=> x=5 (tm)
+)TH2: x<0 thì pt trở thành:
2x=-10 <=> x=-5 (tm)
Vậy x={-5;5}
c) \(\left|2x+1\right|+1=4\Leftrightarrow\left|2x+1\right|=3\)
+)TH1: x>= -1/2 thì pt trở thành:
2x+1=3 <=> x=1 (tm)
+)TH2: x<-1/2 thì pt trở thành:
2x+1=-3 <=> 2x=-4 <=> x=-2 (tm)
Vậy x={-2;1}
a)1,25-|0,5-x|=0
|0,5-x|=1,25
\(\Rightarrow\left[\begin{array}{nghiempt}0,5-x=1,25\\0,5-x=-1,25\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=-0,75\\x=1,75\end{array}\right.\)
Vậy x=-0,75;1,75
b)|2x|-|-3,5|=|-6,5|
|2x|-3,5=6,5
|2x|=10
\(\Rightarrow\left[\begin{array}{nghiempt}2x=10\\2x=-10\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\)
Vậy x=5;-5
c)|2x+1|=4
\(\Rightarrow\left[\begin{array}{nghiempt}2x+1=4\\2x+1=-4\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}2x=3\\2x=-3\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{3}{2}\\x=-\frac{3}{2}\end{array}\right.\)
Vậy \(x=\frac{3}{2};-\frac{3}{2}\)
Ch mk sửa câu c nha
|2x+1|+1=4
|2x+1|=3
\(\Rightarrow\left[\begin{array}{nghiempt}2x+1=3\\2x+1=-3\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=1\\x=-2\end{array}\right.\)
Vậy x=1;-2
