a) \(14x-56=0\)
\(\Leftrightarrow14=0+56=56\)
\(\Leftrightarrow x=4\)
b )\(\frac{1}{2}-\frac{1}{3}x=0\)
\(\Leftrightarrow-\frac{1}{3}x=0-\frac{1}{2}=-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{3}{2}\)
c )\(16-x^2=0\)
\(\Leftrightarrow-x^2=0-16=-16\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow\left[\begin{matrix}x=\sqrt{16}=4\\x=-\sqrt{16}=-4\end{matrix}\right.\)
d) \(\left|x-2\right|+\left(y+3\right)^2\)
\(\Leftrightarrow\left\{\begin{matrix}\left|x-2\right|=0\\\left(y+3\right)^2=0\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}x=2\\y=-3\end{matrix}\right.\)
e) \(\left(x+1\right)^2+2\left|y-1\right|=0\)
\(\Leftrightarrow\left\{\begin{matrix}\left(x+1\right)^2=0\\2\left|y-1\right|=0\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}x=-1\\y=1\end{matrix}\right.\)
a)
\(14x-56=0\)
\(\Leftrightarrow x=4\)
Vậy x=4
b)
\(\frac{1}{2}-\frac{1}{3x}=0\)
\(\Leftrightarrow\frac{1}{2}=\frac{1}{3}.x\)
\(\Leftrightarrow x=\frac{3}{2}\)
c)
\(16-x^2=0\)
\(\Leftrightarrow16=x^2\)
\(\Leftrightarrow\left[\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
Vậy x = 4 ; x = - 4
d)
Vì \(\left\{\begin{matrix}\left|x-2\right|\ge0\\\left(y+3\right)^2\ge0\end{matrix}\right.\)\(\left(\forall x;y\right)\)
\(\Rightarrow\left\{\begin{matrix}x-2=0\\y+3=0\end{matrix}\right.\)
\(\Rightarrow\left\{\begin{matrix}x=2\\y=-3\end{matrix}\right.\)
Vậy x = 2 ; x = - 2
e )
Tương tự câu d)
