Question

Tìm 3 số x,y,z biết x:y:z=2/3:3/5:1/2 và x-y=-6,5

Answer 1

Theo đề bài, ta có:

x:y:z=2/3:3/5:1/2

=> x/2/3=y/3/5=z/1/2

và x-y=-6,5

Theo tính chất dãy tỉ số bằng nhau, ta có:

x/2/3=y/3/5=x-y/2/3-3/5=-6,5/1/15=-13/30

=> x/2/3=-13/30=>x=-13/30.2/3=-13/45

=>y/3/5=-13/45=>y=-13/45.3/5=-13/75

=>z/1/2=-13/45=>z=-13/45.1/2=-13/90

Vậy x=-13/45 ; y=-13/75 ; z=-13/90

Tick cho mình nha!

Answer 2

x:y:z=2/3:3/5:1/2

=>\(\dfrac{x}{\dfrac{2}{3}}=\dfrac{y}{\dfrac{3}{5}}=\dfrac{z}{\dfrac{1}{2}}\)=\(\dfrac{x-y}{\dfrac{2}{3}-\dfrac{3}{5}}=\dfrac{6,5}{\dfrac{1}{15}}=97,5\)

=>\(\dfrac{x}{\dfrac{2}{3}}=97,5\Rightarrow x=65;\dfrac{y}{\dfrac{3}{5}}=97,5\Rightarrow y=58,5\)

\(\dfrac{z}{\dfrac{1}{2}}=97,5\Rightarrow z=48,75\)

vậy .......