Theo bài ra có: \(\dfrac{a}{4}=\dfrac{b}{7}\Rightarrow\dfrac{a}{12}=\dfrac{b}{21}\)
\(5b=3c\Rightarrow\dfrac{b}{3}=\dfrac{c}{5}\Rightarrow\dfrac{b}{21}=\dfrac{c}{35}\)
Khi đó: \(\dfrac{a}{12}=\dfrac{b}{21}=\dfrac{c}{35}\)
\(\Rightarrow\dfrac{2a}{24}=\dfrac{b}{21}=\dfrac{c}{35}\)
Áp dụng tc dãy tỉ số = nhau:
\(\dfrac{2a}{24}=\dfrac{b}{21}=\dfrac{c}{35}=\dfrac{2a-b+c}{24-21+35}=3\)
Do \(\left\{{}\begin{matrix}\dfrac{2a}{24}=3\\\dfrac{b}{21}=1\\\dfrac{c}{35}=3\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a=36\\b=21\\c=105\end{matrix}\right.\).