\(\dfrac{\left(\sqrt{5}+2\right)^2-8\sqrt{5}}{2\sqrt{5}-4}=\dfrac{5+4\sqrt{5}+4-8\sqrt{5}}{2\sqrt{5}-4}=\dfrac{9-4\sqrt{5}}{2\sqrt{5}-4}=\dfrac{\left(9-4\sqrt{5}\right)\left(2\sqrt{5}+4\right)}{20-16}=\dfrac{18\sqrt{5}+36-40-16\sqrt{5}}{4}=\dfrac{2\sqrt{5}-4}{4}=\dfrac{2\left(\sqrt{5}-2\right)}{4}=\dfrac{\sqrt{5}-2}{2}\)