Để cho gọn ta đặt \(\left(2x-15\right)^3=t\) ta được:
\(t^2=t\Rightarrow t^2-t=0\Rightarrow t\left(t-1\right)=0\)
\(\Rightarrow\left[\begin{matrix}t=0\\t=1\end{matrix}\right.\)\(\Rightarrow\left[\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^3=1\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}2x-15=0\\2x-15=1\end{matrix}\right.\)\(\Rightarrow\left[\begin{matrix}2x=15\\2x=16\end{matrix}\right.\)\(\Rightarrow x=8\left(x\in N\right)\)