\(\left|x-5\right|-x=3\)
\(\Rightarrow\left|x-5\right|=3+x\)
\(\Rightarrow x-5=\pm\left(x-3\right)\)
+) \(x-5=x-3\Rightarrow-5=-3\) ( vô lí )
+) \(x-5=-\left(x-3\right)\)
\(\Rightarrow x-5=-x-3\)
\(\Rightarrow x+x=-3+5\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)