Phương trình chứa căn
Các câu hỏi tương tự
Giải các phương trình sau:1) sqrt{3x^2+5x+8}-sqrt{3x^2+5x+1}12) x^2-2x-12+4sqrt{left(4-xright)left(2+xright)}03) 3sqrt{x}+dfrac{3}{2sqrt{x}}2x+dfrac{1}{2x}-74) sqrt{x}-dfrac{4}{sqrt{x+2}}+sqrt{x+2}05)left(x-7right)sqrt{dfrac{x+3}{x-7}}x+46) 2sqrt{x-4}+sqrt{x-1}sqrt{2x-3}+sqrt{4x-16}7) sqrt{x+2sqrt{x-1}}+sqrt{x-2sqrt{x-1}}dfrac{x+3}{2}Giúp mình với ajk, mink đang cần gấp
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Giải các phương trình sau:
1) \(\sqrt{3x^2+5x+8}-\sqrt{3x^2+5x+1}=1\)
2) \(x^2-2x-12+4\sqrt{\left(4-x\right)\left(2+x\right)}=0\)
3) \(3\sqrt{x}+\dfrac{3}{2\sqrt{x}}=2x+\dfrac{1}{2x}-7\)
4) \(\sqrt{x}-\dfrac{4}{\sqrt{x+2}}+\sqrt{x+2}=0\)
5)\(\left(x-7\right)\sqrt{\dfrac{x+3}{x-7}}=x+4\)
6) \(2\sqrt{x-4}+\sqrt{x-1}=\sqrt{2x-3}+\sqrt{4x-16}\)
7) \(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=\dfrac{x+3}{2}\)
Giúp mình với ajk, mink đang cần gấp
1, \(x^3-x-3=2\sqrt{6x-x^2}\)
2, \(x^3+6x^2-171x-40\left(x+1\right)\sqrt{5x-1}+20=0\)
3, \(\sqrt[3]{x+3}+\sqrt[3]{x-3}=\sqrt[5]{x-5}+\sqrt[5]{x+5}\)
4. \(\left(\frac{1}{\sqrt{x}}-\frac{\sqrt{x}}{x+1}\right)^2=\frac{4\left(1+\sqrt{1+4x}\right)}{x+1+\sqrt{x^2+3x+2}}\)
Giai pt
1,sqrt{x+8-6sqrt{x-1}}4
2,sqrt{x+6-2sqrt{x+2}}+sqrt{x+11-6sqrt{x+2}}1
3,sqrt{x-3-2sqrt{x-4}}+sqrt{x-4sqrt{x-4}}1
4,sqrt{x-2+sqrt{2x+5}}+sqrt{x+2+3sqrt{2x-5}}dfrac{7}{2}
5,sqrt{2x+4+6sqrt{2x-5}}+sqrt{2x-4-2sqrt{2x-5}}4
6,sqrt{dfrac{1}{4}x^2+x+1}-sqrt{6-2sqrt{5}}0
7,x+sqrt{x+dfrac{1}{2}}+sqrt{x+dfrac{1}{4}}2
8,sqrt{left(x-1right)+4-4sqrt{x-1}}+sqrt{x-1-6sqrt{x-1+9}}1
9,sqrt{x+2sqrt{x-1}}+sqrt{x-2sqrt{x-1}}dfrac{x+3}{2}
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Giai pt
1,\(\sqrt{x+8-6\sqrt{x-1}}\)=4
2,\(\sqrt{x+6-2\sqrt{x+2}}\)+\(\sqrt{x+11-6\sqrt{x+2}}\)=1
3,\(\sqrt{x-3-2\sqrt{x-4}}\)+\(\sqrt{x-4\sqrt{x-4}}\)=1
4,\(\sqrt{x-2+\sqrt{2x+5}}\)+\(\sqrt{x+2+3\sqrt{2x-5}}\)=\(\dfrac{7}{2}\)
5,\(\sqrt{2x+4+6\sqrt{2x-5}}\)+\(\sqrt{2x-4-2\sqrt{2x-5}}\)=4
6,\(\sqrt{\dfrac{1}{4}x^2+x+1}\)-\(\sqrt{6-2\sqrt{5}}\)=0
7,x+\(\sqrt{x+\dfrac{1}{2}}\)+\(\sqrt{x+\dfrac{1}{4}}\)=2
8,\(\sqrt{\left(x-1\right)+4-4\sqrt{x-1}}+\sqrt{x-1-6\sqrt{x-1+9}}\)=1
9,\(\sqrt{x+2\sqrt{x-1}}\)+\(\sqrt{x-2\sqrt{x-1}}\)=\(\dfrac{x+3}{2}\)
1.\(\sqrt{\frac{\left(1-x\right)}{x}}=\frac{\left(2x+x^2\right)}{1+x^2}\)
2. 3(2-\(\sqrt{x+2}\))=2x+\(\sqrt{x+6}\)
3. \(\sqrt[3]{x+2}+\sqrt[3]{x+1}=\sqrt[2]{2x^2}+\sqrt[3]{2x^2+1}\)
4. \(\sqrt[3]{x+24}+\sqrt{12-x}=6\)
Toán 10 ạ, giúp em với
Giải phương trình :
a. (sqrt{x+4} -2)(sqrt{4-x} -2) -2x
b. 2.sqrt[3]{6x-2} + 3sqrt{6-10x} 8
c. sqrt[3]{x+2} + sqrt[3]{14-x} 4
d. sqrt{5x-1} - sqrt{3x+13} frac{x-7}{3}
giúp em với đang cần gấp ạ ?
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Giải phương trình :
a. (\(\sqrt{x+4}\) -2)(\(\sqrt{4-x}\) -2)= -2x
b. 2.\(\sqrt[3]{6x-2}\) + 3\(\sqrt{6-10x}\) = 8
c. \(\sqrt[3]{x+2}\) + \(\sqrt[3]{14-x}\) = 4
d. \(\sqrt{5x-1}\) - \(\sqrt{3x+13}\) = \(\frac{x-7}{3}\)
giúp em với đang cần gấp ạ ?
Giải giúp mih phương trình này đi mà............
a, x2-6x+9=\(4\sqrt{x^2-6x+6}\)
b, x2+\(\sqrt{x^2+11}\) =31
tìm nghiệm (x;y) với x là số nguyên dương của pt sau
\(\sqrt{20-8x}+\sqrt{6x^2-y^2}=y\sqrt{7-4x}\)
Giải phương trình:
1. \(x\sqrt{x}+\dfrac{32}{x\sqrt{x}}=6\sqrt[3]{3x-4}\)
2. \(\sqrt{x^2+x-1}+\sqrt{-x^2+x+1}=x^2-x+2\)
3. \(\sqrt{8-x^2}+\sqrt{\dfrac{x^2-2}{2x^2}}=5-\dfrac{1+x^2}{x}\)
4. \(x^4-12x^3+38x^2-12x-67+\sqrt{x+1}+\sqrt{7-x}=0\)
1)begin{cases}sqrt{4x^2+left(4x-9right)left(x-3yright)}+sqrt{3xy}9y4sqrt{left(x+2right)left(3y+2xright)}3x+9end{cases} 4)begin{cases}left(x^2+yright)sqrt{x-y+6}2x^2-x+3y-2sqrt{10x-xy-12}+1frac{y-x}{sqrt{y-4}+sqrt{6-x}}end{cases}2)begin{cases}x^2+left(y-6right)^2y+13x+27sqrt{9x^2+left(2x-3right)left(x-yright)}+4sqrt{xy}7yend{cases} 5)begin{cases}sqrt{4xy+left(3sqrt{xy}-7right)left(x-yright)}+2sqrt{xy}4yle...
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1)\(\begin{cases}\sqrt{4x^2+\left(4x-9\right)\left(x-3y\right)}+\sqrt{3xy}=9y\\4\sqrt{\left(x+2\right)\left(3y+2x\right)}=3x+9\end{cases}\) 4)\(\begin{cases}\left(x^2+y\right)\sqrt{x-y+6}=2x^2-x+3y-2\\\sqrt{10x-xy-12}+1=\frac{y-x}{\sqrt{y-4}+\sqrt{6-x}}\end{cases}\)
2)\(\begin{cases}x^2+\left(y-6\right)^2=y+13x+27\\\sqrt{9x^2+\left(2x-3\right)\left(x-y\right)}+4\sqrt{xy}=7y\end{cases}\) 5)\(\begin{cases}\sqrt{4xy+\left(3\sqrt{xy}-7\right)\left(x-y\right)}+2\sqrt{xy}=4y\\\left(2x+1\right)\left[12y-1+9\sqrt{xy}-x^2-x\right]=27\left(x+1\right)\end{cases}\)
3)\(\begin{cases}\sqrt{\left(x+2\right)\left(y+1\right)+\left(x-y+1\right)\sqrt{y^2+1}}+\sqrt{x+2}=y+\sqrt{y+1}+1\\\sqrt{3x+1}-\sqrt{y+1}=2x^2+4x-y-1\end{cases}\)