\(\sqrt{7+4\sqrt{3}}.\sqrt{7-4\sqrt{3}}=\sqrt{\left(7+4\sqrt{3}\right)\left(7-4\sqrt{3}\right)}=\sqrt{49-48}=1\)
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Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
\(\sqrt{3-2\sqrt{2}}-\sqrt{11+6\sqrt{2}}\)
\(\sqrt{4-2\sqrt{3}}-\sqrt{7-4\sqrt{3}}+\sqrt{19+8\sqrt{3}}\)
\(\sqrt{6-2\sqrt{5}}+\sqrt{9+4\sqrt{5}}-\sqrt{14-6\sqrt{5}}\)
\(\sqrt{11-4\sqrt{7}}+\sqrt{23-8\sqrt{7}}+\sqrt{\left(-2^6\right)}\)
rút gọn:giải chi tiết hộ mình nha
1) \(\sqrt{7-2\sqrt{10}}\) - \(\sqrt{7+2\sqrt{10}}\)
2) \(\sqrt{4-2\sqrt{3}}\) + \(\sqrt{4+2\sqrt{3}}\)
3) \(\sqrt{6-4\sqrt{2}}\) + \(\sqrt{22-12\sqrt{2}}\)
Không dùng máy tính hãy so sánh:
\(A=\dfrac{3+\sqrt{5}}{2\sqrt{2}+\sqrt{3+\sqrt{5}}}+\dfrac{3-\sqrt{5}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
\(B=\dfrac{4+\sqrt{7}}{3\sqrt{2}+\sqrt{4+\sqrt{7}}}+\dfrac{4-\sqrt{7}}{3\sqrt{2}-\sqrt{4-\sqrt{7}}}\)
Tính: a. left(sqrt{10}+sqrt{2}right)cdotleft(6-2sqrt{5}right)cdotsqrt{3+sqrt{5}}
b. sqrt{3+sqrt{5}}-sqrt{3-sqrt{5}}-sqrt{2}
c. sqrt{3,5-sqrt{6}}+sqrt{3,5+sqrt{6}}
d, sqrt{4-sqrt{7}}-sqrt{4+sqrt{7}}+sqrt{7}
e, sqrt{4+sqrt{7}}-sqrt{4-sqrt{7}}-sqrt{2}
Đọc tiếp
Tính: a. \(\left(\sqrt{10}+\sqrt{2}\right)\cdot\left(6-2\sqrt{5}\right)\cdot\sqrt{3+\sqrt{5}}\)
b. \(\sqrt{3+\sqrt{5}}-\sqrt{3-\sqrt{5}}-\sqrt{2}\)
c. \(\sqrt{3,5-\sqrt{6}}+\sqrt{3,5+\sqrt{6}}\)
d, \(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}+\sqrt{7}\)
e, \(\sqrt{4+\sqrt{7}}-\sqrt{4-\sqrt{7}}-\sqrt{2}\)
Tính giá trị các biểu thức sau
1.dfrac{1}{sqrt{1}-sqrt{2}}-dfrac{1}{sqrt{2}-sqrt{3}}+dfrac{1}{sqrt{3}-sqrt{4}}-dfrac{1}{sqrt{4}-sqrt{5}}+dfrac{1}{sqrt{5}-sqrt{6}}-dfrac{1}{sqrt{6}-sqrt{7}}+dfrac{1}{sqrt{7}-sqrt{8}}-dfrac{1}{sqrt{8}-sqrt{9}}
2.dfrac{1}{2sqrt{1}+1sqrt{2}}+dfrac{1}{3sqrt{2}+2sqrt{3}}+dfrac{1}{4sqrt{3}+3sqrt{4}}+dfrac{1}{5sqrt{4}+4sqrt{5}}+dfrac{1}{6sqrt{5}+5sqrt{6}}+dfrac{1}{7sqrt{6}+6sqrt{7}}
giúp mk vs ạ
Đọc tiếp
Tính giá trị các biểu thức sau
1.\(\dfrac{1}{\sqrt{1}-\sqrt{2}}-\dfrac{1}{\sqrt{2}-\sqrt{3}}+\dfrac{1}{\sqrt{3}-\sqrt{4}}-\dfrac{1}{\sqrt{4}-\sqrt{5}}+\dfrac{1}{\sqrt{5}-\sqrt{6}}-\dfrac{1}{\sqrt{6}-\sqrt{7}}+\dfrac{1}{\sqrt{7}-\sqrt{8}}-\dfrac{1}{\sqrt{8}-\sqrt{9}}\)
2.\(\dfrac{1}{2\sqrt{1}+1\sqrt{2}}+\dfrac{1}{3\sqrt{2}+2\sqrt{3}}+\dfrac{1}{4\sqrt{3}+3\sqrt{4}}+\dfrac{1}{5\sqrt{4}+4\sqrt{5}}+\dfrac{1}{6\sqrt{5}+5\sqrt{6}}+\dfrac{1}{7\sqrt{6}+6\sqrt{7}}\)
giúp mk vs ạ
tính :giải chi tiết nha
\(\sqrt{7-4\sqrt{3}}\)
\(\sqrt{9+4\sqrt{5}}\)
\(\sqrt{11-4\sqrt{7}}\)
Tính
\(a.\sqrt{5-2\sqrt{5}}+\sqrt{5+2\sqrt{5}}\)
\(b.\sqrt{7-4\sqrt{3}}+\sqrt{7+4\sqrt{3}}\)
\(c.\sqrt{13-4\sqrt{3}}+\sqrt{13+4\sqrt{3}}\)
rút gon bieu thức
left(3sqrt{2}+sqrt{6}right).sqrt{6-3sqrt{3}}
sqrt{12-3sqrt{7}}-sqrt{12+3sqrt{7}}
sqrt{dfrac{13}{4}+sqrt{3}}-sqrt{dfrac{7}{4}-sqrt{3}}
sqrt{dfrac{289+4sqrt{72}}{16}}+sqrt{dfrac{129}{16}+sqrt{2}}
sqrt{11+6sqrt{2}}-sqrt{sqrt{8}+3}
sqrt{16-6sqrt{7}}+sqrt{10-2sqrt{21}}
Đọc tiếp
rút gon bieu thức
\(\left(3\sqrt{2}+\sqrt{6}\right).\sqrt{6-3\sqrt{3}}\)
\(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
\(\sqrt{\dfrac{13}{4}+\sqrt{3}}-\sqrt{\dfrac{7}{4}-\sqrt{3}}\)
\(\sqrt{\dfrac{289+4\sqrt{72}}{16}}+\sqrt{\dfrac{129}{16}+\sqrt{2}}\)
\(\sqrt{11+6\sqrt{2}}-\sqrt{\sqrt{8}+3}\)
\(\sqrt{16-6\sqrt{7}}+\sqrt{10-2\sqrt{21}}\)
Tính giá trị các biểu thức:
a/ \(\sqrt{7+\sqrt{7^2-4}}-\sqrt{7-\sqrt{7^2-4}}\)
b/ \(2\sqrt{40\sqrt{12}}-2\sqrt{\sqrt{75}}-3\sqrt{5\sqrt{48}}\)
c/ \(\left(\dfrac{1}{2+\sqrt{3}}-\dfrac{12}{3+\sqrt{3}}+\dfrac{26}{4-\sqrt{3}}\right)\cdot\left(4-3\sqrt{3}\right)\)