Lời giải:
ĐKXĐ: $x\geq 5$
PT \(\Leftrightarrow \sqrt{4}.\sqrt{x-5}+\sqrt{x-5}-\frac{1}{3}.\sqrt{9}.\sqrt{x-5}=4\)
\(\Leftrightarrow 2\sqrt{x-5}+\sqrt{x-5}-\sqrt{x-5}=4\)
\(\Leftrightarrow 2\sqrt{x-5}=4\Leftrightarrow \sqrt{x-5}=2\)
\(\Rightarrow x=2^2+5=9\) (thỏa mãn)
Vậy..........