Đặt \(\left\{{}\begin{matrix}\sqrt[4]{2x+1}=a\\\sqrt[4]{1-x}=b\\\sqrt[4]{x+2}=c\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a+b=c\\a^4+b^4-c^4=0\end{matrix}\right.\)
\(\Rightarrow a^4+b^4=\left(a+b\right)^4\)
\(\Leftrightarrow ab\left(2a^2+3ab+2b^2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}a=0\\b=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=-\frac{1}{2}\\x=1\end{matrix}\right.\)
Giai pt
1,\(\sqrt{x+8-6\sqrt{x-1}}\)=4
2,\(\sqrt{x+6-2\sqrt{x+2}}\)+\(\sqrt{x+11-6\sqrt{x+2}}\)=1
3,\(\sqrt{x-3-2\sqrt{x-4}}\)+\(\sqrt{x-4\sqrt{x-4}}\)=1
4,\(\sqrt{x-2+\sqrt{2x+5}}\)+\(\sqrt{x+2+3\sqrt{2x-5}}\)=\(\dfrac{7}{2}\)
5,\(\sqrt{2x+4+6\sqrt{2x-5}}\)+\(\sqrt{2x-4-2\sqrt{2x-5}}\)=4
6,\(\sqrt{\dfrac{1}{4}x^2+x+1}\)-\(\sqrt{6-2\sqrt{5}}\)=0
7,x+\(\sqrt{x+\dfrac{1}{2}}\)+\(\sqrt{x+\dfrac{1}{4}}\)=2
8,\(\sqrt{\left(x-1\right)+4-4\sqrt{x-1}}+\sqrt{x-1-6\sqrt{x-1+9}}\)=1
9,\(\sqrt{x+2\sqrt{x-1}}\)+\(\sqrt{x-2\sqrt{x-1}}\)=\(\dfrac{x+3}{2}\)
Giải các phương trình sau:
1) \(\sqrt{3x^2+5x+8}-\sqrt{3x^2+5x+1}=1\)
2) \(x^2-2x-12+4\sqrt{\left(4-x\right)\left(2+x\right)}=0\)
3) \(3\sqrt{x}+\dfrac{3}{2\sqrt{x}}=2x+\dfrac{1}{2x}-7\)
4) \(\sqrt{x}-\dfrac{4}{\sqrt{x+2}}+\sqrt{x+2}=0\)
5)\(\left(x-7\right)\sqrt{\dfrac{x+3}{x-7}}=x+4\)
6) \(2\sqrt{x-4}+\sqrt{x-1}=\sqrt{2x-3}+\sqrt{4x-16}\)
7) \(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=\dfrac{x+3}{2}\)
Giúp mình với ajk, mink đang cần gấp
a)\(\sqrt{4x-1}+\sqrt{4x^2-1}=1\)
b)\(x+4\sqrt{x+3}+2\sqrt{3-2x}=11\)
c)\(\sqrt{x}-x=1-\sqrt{2x+1}\)
d)\(\sqrt{x}+\sqrt{4-x}-2=-x\)
e)\(\sqrt{4+x}+x=\sqrt{4+12x}\)
Tìm x:
a.\(\sqrt{4-\sqrt{4+x}}=x\)
b.\(4\left(\sqrt{x-1}-3\right)x^2+\left(13\sqrt{x+1}-8\right)x-4\sqrt{x-1}-3=0\)
c.\(\sqrt{2x-3}+2\sqrt{x-3}\ge3\sqrt[4]{2x^2+x-6}\)
2 ( 2x+1 ) \sqrt{ x+1 } + ( 4-x ) \sqrt{ 2-2x } = 6 \sqrt{ x ^{ 2 } +2 }
giải pt
a) \(\sqrt{3x-2}-\sqrt{5-x}=\sqrt{2x-4}\)
b) 2(1-x)\(\sqrt{x^2+2x-1}\) = 4-2x
Giải phương trình:
1) \(\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=1\)
2) \(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
gpt :A= \(2x^2-5x-1=\sqrt{x+2}+\sqrt{4-x}\)
B= \(\sqrt{x^2-2x+5}+2\sqrt{4x+5}=x^3-2x^2+5x+4\)
Giải phương trình:
1. \(x\sqrt{x}+\dfrac{32}{x\sqrt{x}}=6\sqrt[3]{3x-4}\)
2. \(\sqrt{x^2+x-1}+\sqrt{-x^2+x+1}=x^2-x+2\)
3. \(\sqrt{8-x^2}+\sqrt{\dfrac{x^2-2}{2x^2}}=5-\dfrac{1+x^2}{x}\)
4. \(x^4-12x^3+38x^2-12x-67+\sqrt{x+1}+\sqrt{7-x}=0\)
