Câu hỏi của Linh Nhi

Question

$\sqrt{25x+75}+3\sqrt{x-2}=2+4\sqrt{x+3}+\sqrt{9x-18}$

Hắc Hường · Accepted Answer

Giải:

$\sqrt{25x+75}+3\sqrt{x-2}=2+4\sqrt{x+3}+\sqrt{9x-18}$

$\Leftrightarrow5\sqrt{x+3}+3\sqrt{x-2}=2+4\sqrt{x+3}+3\sqrt{x-2}$

$\Leftrightarrow5\sqrt{x+3}=2+4\sqrt{x+3}$

$\Leftrightarrow\sqrt{x+3}=2$

$\Leftrightarrow x+3=4$

$\Leftrightarrow x=1$

Vậy ...Câu trả lời: Giải:

$\sqrt{25x+75}+3\sqrt{x-2}=2+4\sqrt{x+3}+\sqrt{9x-18}$

$\Leftrightarrow5\sqrt{x+3}+3\sqrt{x-2}=2+4\sqrt{x+3}+3\sqrt{x-2}$

$\Leftrightarrow5\sqrt{x+3}=2+4\sqrt{x+3}$

$\Leftrightarrow\sqrt{x+3}=2$

$\Leftrightarrow x+3=4$

$\Leftrightarrow x=1$

Vậy ...

Hắc Hường · Answer

Giải:

$\sqrt{25x+75}+3\sqrt{x-2}=2+4\sqrt{x+3}+\sqrt{9x-18}$

$\Leftrightarrow6\sqrt{x+3}+3\sqrt{x-2}=2+4\sqrt{x+3}+3\sqrt{x-2}$

$\Leftrightarrow6\sqrt{x+3}=2+4\sqrt{x+3}$

$\Leftrightarrow2\sqrt{x+3}=2$

$\Leftrightarrow\sqrt{x+3}=1$

$\Leftrightarrow x+3=1$

$\Leftrightarrow x=-2$

Vậy ...Câu trả lời: Giải:

$\sqrt{25x+75}+3\sqrt{x-2}=2+4\sqrt{x+3}+\sqrt{9x-18}$

$\Leftrightarrow6\sqrt{x+3}+3\sqrt{x-2}=2+4\sqrt{x+3}+3\sqrt{x-2}$

$\Leftrightarrow6\sqrt{x+3}=2+4\sqrt{x+3}$

$\Leftrightarrow2\sqrt{x+3}=2$

$\Leftrightarrow\sqrt{x+3}=1$

$\Leftrightarrow x+3=1$

$\Leftrightarrow x=-2$

Vậy ...

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