Question

\(\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\)

Answer 1

Answer 2

\(\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}=\dfrac{\sqrt{3-2\sqrt{3}+1}+\sqrt{3+2\sqrt{3}+1}}{\sqrt{2}}=\dfrac{\sqrt{3}-1+\sqrt{3}+1}{\sqrt{2}}=\dfrac{2\sqrt{3}}{\sqrt{2}}=\sqrt{6}\)

Answer 3

\(\sqrt{2-\sqrt{3}}\)+\(\sqrt{2+\sqrt{3}}\)

=2ʌ2-\(\sqrt{3}\)ʌ2

=4-3

=1