Question

\(\sqrt{14-6\sqrt{5}}\)

\(\sqrt{28-12\sqrt{5}}\)

\(\sqrt{7-3\sqrt{5}}\)

\(\left(3-\sqrt{2}\right)\sqrt{11+6\sqrt{2}}\)

\(\sqrt{11-6\sqrt{2}+\sqrt{3-2\sqrt{2}}}\)

giải hộ mình với ạ, làm chi tiết 1 tí ạ

Answer 1

a) \(\sqrt{14-6\sqrt{5}}=\sqrt{\left(3-\sqrt{5}\right)^2}=3-\sqrt{5}\)

b, c) tương tự câu a.

d) \(\left(3-\sqrt{2}\right)\sqrt{11+6\sqrt{2}}\)

\(=\left(3-\sqrt{2}\right)\sqrt{\left(3+\sqrt{2}\right)^2}\)

\(=\left(3-\sqrt{2}\right)\left(3+\sqrt{2}\right)\)

\(=9-2\)

\(=7\)

e) \(\sqrt{11-6\sqrt{2}+\sqrt{3-2\sqrt{2}}}\)

\(=\sqrt{11-6\sqrt{2}+\sqrt{\left(1-\sqrt{2}\right)^2}}\)

\(=\sqrt{11-6\sqrt{2}+\sqrt{2}-1}\)

\(=\sqrt{10-5\sqrt{2}}\)