Có:\(\sqrt{48}< \sqrt{49}=7\)
\(13-\sqrt{35}>13-\sqrt{36}=7\)
\(\Rightarrow\sqrt{48}< 13-\sqrt{35}\)
\(\sqrt{48}+\sqrt{35}< \sqrt{49}+\sqrt{36}=7+6=13\)
\(\rightarrow\sqrt{48}< 13-\sqrt{35}\)
Ta có:
\(\sqrt{48}< \sqrt{49}=7\left(1\right)\)
\(13-\sqrt{35}>13-\sqrt{36}=13-6=7\left(2\right)\)
Từ (1) và (2) :
Suy ra: \(\sqrt{48}< 13-\sqrt{35}\)
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