Ta có \(6=\sqrt{36}\)
\(\sqrt{37}-\sqrt{14}=\sqrt{37}+\left(-\sqrt{14}\right)\)
\(6-\sqrt{15}=\sqrt{36}-\sqrt{15}=\sqrt{36}+\left(-\sqrt{15}\right)\)
Vì \(\sqrt{37}>\sqrt{36}\) và \(-\sqrt{14}>-\sqrt{15}\)
\(\Rightarrow\sqrt{37}+\left(-\sqrt{14}\right)>\sqrt{36}+\left(-\sqrt{15}\right)\)
\(\Rightarrow\sqrt{37}-\sqrt{14}>\sqrt{36}-\sqrt{15}\)
hay \(\sqrt{37}-\sqrt{14}>6-\sqrt{15}\)
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