a/ Có: \(2\sqrt{3}=\sqrt{12};3\sqrt{2}=\sqrt{18}\)
Ta có: \(\sqrt{12}< \sqrt{18}\Rightarrow2\sqrt{3}< 3\sqrt{2}\)
b/ Có: \(\sqrt{15}>\sqrt{7}\Rightarrow\sqrt{15}+\sqrt{7}>\sqrt{7}\)
b/ (đề bạn nói ở cmt)
Ta có: \(\sqrt{7}< \sqrt{9}=3;\sqrt{15}< \sqrt{16}=4\)
\(\Rightarrow\sqrt{7}+\sqrt{15}< 3+4=7\)
vậy \(\sqrt{7}+\sqrt{15}< 7\)