a.
\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}=\left(2^3\right)^{100}=2^{300}\)
Vậy \(3^{200}>2^{300}\)
b.
\(5^{200}=\left(5^2\right)^{100}=25^{100}< 32^{100}=\left(2^5\right)^{100}=2^{500}\)
Vậy \(5^{200}< 2^{500}\)
Ta có : \(3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)
\(2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)
\(\Rightarrow9^{100}>8^{100}\)
\(\Rightarrow3^{200}>2^{300}\)
Ta có : \(5^{200}=5^{2.100}=\left(5^2\right)^{100}=25^{100}\)
\(2^{500}=2^{5.100}=\left(2^5\right)^{100}=32^{100}\)
\(\Rightarrow25^{100}< 32^{100}\)
\(\Rightarrow5^{200}< 2^{500}\)