\(\left(\dfrac{8-x\sqrt{x}}{2-\sqrt{x}}+2\sqrt{x}\right)\left(\dfrac{2-\sqrt{x}}{2+\sqrt{x}}\right)^2=\left(x+2\sqrt{x}+4+2\sqrt{x}\right).\dfrac{\left(2-\sqrt{x}\right)^2}{\left(\sqrt{x}+2\right)^2}=\left(\sqrt{x}+2\right)^2.\dfrac{\left(\sqrt{x}-2\right)^2}{\left(\sqrt{x}+2\right)^2}=\left(\sqrt{x}-2\right)^2\)