ĐKXĐ: bạn tự tìm
\(A=\sqrt{x-2-2\sqrt{x-2}+1}+\sqrt{x-2+2\sqrt{x-2}+1}\)
\(=\sqrt{\left(\sqrt{x-2}-1\right)^2}+\sqrt{\left(\sqrt{x-2}+1\right)^2}\)
\(=\left|\sqrt{x-2}-1\right|+\sqrt{x-2}+1\)
\(=\left[{}\begin{matrix}2\sqrt{x-2}\left(x\ge3\right)\\2\left(2\le x< 3\right)\end{matrix}\right.\)
\(B=\sqrt{\left(x-2\right)^2}+\frac{x-2}{\sqrt{\left(x-2\right)^2}}=\left|x-2\right|+\frac{x-2}{\left|x-2\right|}\)
\(=\left[{}\begin{matrix}x-1\left(x>2\right)\\1-x\left(x< 2\right)\end{matrix}\right.\)