Question

phân tích đa thức thành nhân tử = p² dùng HĐTĐN

1) ( 3x + 2 )² - 4

2) ( 2x + 1 )² - ( x - 1)²

3) x³ + 729

4) 27a³ - 64b⁶

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Answer 1

a) \(\left(3x+2\right)^2-4=\left(3x+2-2\right)\left(3x+2+2\right)=3x\left(3x+4\right)\)

b) \(\left(2x+1\right)^2-\left(x-1\right)^2=\left(2x+1+x-1\right)\left(2x+1-x+1\right)=3x\left(x+2\right)\)

c) \(x^3+729=x^3+9^3=\left(x+9\right)\left(x^2-9x+81\right)\)

d) \(27a^3-64b^6=\left(3a\right)^3-\left(4b^2\right)^3=\left(3a-4b^2\right)\left(9a^2+12ab^2+16b^4\right)\)