Question

Phân tích đa thức thành nhân tử:

\(a,2x^3y-2xy^3-4xy^2-2xy\)

\(b,3x^2+6xy+3y^2-12\)

\(c,x^2+5x+6\)

Answer 1

c, \(x^2\) + 5x + 6

= \(x^2\) + 2x + 3x +6

= (\(x^2\) + 2x) + (3x + 6)

= x(x + 2) + 3(x + 2)

= (x + 2)(x + 3)

Answer 2

b, \(2x^3y-2xy^3-4xy^2-2xy\)

= 2xy(\(x^2\) - \(y^2\) - \(2y\) - 1)

= 2xy(\(x^2-\left(y^2+2y+1\right)\))

= 2xy(\(x^2\) \(-\left(y+1\right)^2\))

= 2xy(\(x^2-y-1\))(\(x^2+y+1\))

Answer 3

c, \(3x^2+6xy+3y^2-12\)

= 3(\(x^2+2xy+y^2-4\))

= 3(\(x^2+2xy+y^2\))\(-4\)

= 3(\(\left(x+y\right)^2\)\(-4\))

= 3\(\left(x+y+2\right)\left(x+y-2\right)\)