Question

Phân tích các đa thức sau thành phân tử:

x³-6x²+12x-8(x-1)²-25x²36x²-(2x+1)²(x+3)²-(2x-1)²

Answer 1

1) (x-2)³

2) (x-1+5x)(x-1-5x)=(6x-1)(-4x-1)

3) (6x-2x-1)(6x+2x+1)=(4x-1)(8x+1)

4) (x+3-2x+1)(x+3+2x-1) = (4-x)(3x+2)

Answer 2

1. \(x^3-6x^2+12x-8=\left(x-2\right)^3\)

2. \(\left(x-1\right)^2-25x^2=\left(x-1-5x\right)\left(x-1+5x\right)\)

= \(\left(-4x-1\right)\left(6x-1\right)\)

3. \(36x^2-\left(2x+1\right)^2=\left(6x-2x-1\right)\left(6x+2x+1\right)\)

= \(\left(4x-1\right)\left(8x+1\right)\)

4. \(\left(x+3\right)^2-\left(2x-1\right)^2=\left(x+3-2x+1\right)\left(x+3+2x-1\right)\)

= \(\left(4-x\right)\left(3x+2\right)\)

Chúc bạn làm bài tốt

Answer 3

1)(x-2)³

2)<=>(x-1-5)(x-1+5)

<=>(x-6)(x+4)

<=>\(\begin{cases}x=6\\x=-4\end{cases}\)

3)<=>(6x-2x-1)(6x+2x+1)

<=>(4x-1)(8x+1)

<=>\(\begin{cases}x=\frac{1}{4}\\x=\frac{-1}{8}\end{cases}\)

4)(x+3)²-(2x-1)²

<=>(x+3-2x+1)(x+3+2x+1)

<=>(4-x)(3x+4)

<=>\(\begin{cases}x=4\\x=\frac{-4}{3}\end{cases}\)

Answer 4

câu 2 sai tý nhé...

(x-1-5x)(x-1+5x)

<=>(-1-4x)(4x+1)