Đổi \(1kg=1000g\)
PTHH: \(CaCO_3\underrightarrow{t^o}CaO+CO_2\)
Ta có: \(n_{CaCO_3}=\dfrac{1000}{100}=10\left(mol\right)=n_{CaO}\)
\(\Rightarrow m_{CaO\left(lýthuyết\right)}=10\cdot56=560\left(g\right)\) \(\Rightarrow m_{CaO\left(thựctế\right)}=560\cdot80\%=448\left(g\right)=0,448\left(kg\right)\)