Question

nay voi
giup minh cau voi

Answer 1

a: \(A=\dfrac{x^2+2x+1-1}{2\left(x-1\right)\left(x+1\right)}\cdot\dfrac{2\left(x+1\right)}{x+2}\)

\(=\dfrac{x\left(x+2\right)}{2\left(x-1\right)}\cdot\dfrac{2}{x+2}=\dfrac{x}{x-1}\)

b: x(x-2)-(x-2)=0

=>(x-2)(x-1)=0

=>x=2(nhận) hoặc x=1(loại)

Khi x=2 thì A=2/(2-1)=2