Ta có:
\(V_{tb}=\dfrac{S_1+S_2}{t_1+t_2}=\dfrac{2S}{\dfrac{S}{V_1}+\dfrac{S}{V_2}}=\dfrac{2S}{\dfrac{SV_2+SV_1}{V_1V_2}}=\dfrac{2V_1V_2}{V_2+V_1}.\)
Thay số ta có:
\(8=\dfrac{2\cdot12\cdot V_2}{12+V_2}\Leftrightarrow 96+8V_2=24V_2 \Leftrightarrow 96=16V_2\Leftrightarrow V_2=6 \left(\dfrac{km}{h}\right)\)
Vậy V2=6km/h