Tóm tắt:
\(m_1=1,5kg\)
\(V=4l\Rightarrow m_2=4kg\)
\(t_1=15^oC\)
\(t_2=100^oC\)
\(\Rightarrow\Delta t=85^oC\)
\(c_1=380J/kg.K\)
\(c_2=4200J/kg.K\)
=========
\(Q=?J\)
Nhiệt lượng cần truyền:
\(Q=Q_1+Q_2\)
\(\Leftrightarrow Q=m_1.c_1.\Delta t+m_2.c_2.\Delta t\)
\(\Leftrightarrow Q=1,5.880.85+4.4200.85\)
\(\Leftrightarrow Q=1540200J\)