Question

Mn giúp em với ạ

Answer 1

a: \(Q=\dfrac{x+2\sqrt{x}-x-\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}\cdot\dfrac{x+\sqrt{x}+1}{\sqrt{x}+2}\)

\(=\dfrac{1}{\sqrt{x}+2}\)

b: Khi \(x=4+2\sqrt{3}\) thì \(Q=\dfrac{1}{\sqrt{3}+1+2}=\dfrac{1}{3+\sqrt{3}}=\dfrac{3-\sqrt{3}}{6}\)