Question

Mình cần cực kì gấp mong b nào đó trl dùm😭

Answer 1

\(a,n_{H_2}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)

PTHH: Mg + 2HCl ---> MgCl₂ + H₂ 

           0,3<--0,6<-------0,3<----0,3

=> m_Mg = 0,3.24 = 7,2 (g)

\(b,m_{ddHCl}=\dfrac{0,6.36.5}{15\%}=146\left(g\right)\\ \rightarrow m_{dd}=146+7,2-0,3.2=152,6\left(g\right)\\ \rightarrow C\%_{MgCl_2}=\dfrac{0,3.95}{152,6}.100\%=18,7\%\)

\(c,n_{NaOH}=0,5.2=1\left(mol\right)\\ \rightarrow C_{M\left(NaOH\right)}=\dfrac{1}{0,2+0,7}=1,4285M\)