Question

Mik cần trình bày rõ ràng ạ, mik cảm ơn

Answer 1

Ta có:

\(A=\dfrac{\sqrt{x}-x}{\sqrt{x}-1}=\dfrac{-\sqrt{x}\left(\sqrt{x}-1\right)}{\sqrt{x}-1}=-\sqrt{x}\)

Vậy \(A=-\sqrt{x}\)

Answer 2

\(A=\dfrac{-\sqrt{x}\left(\sqrt{x}-1\right)}{\sqrt{x}-1}=-\sqrt{x}\)

Answer 3

\(=\sqrt{x}\)