\(M=4^{10}+4^{11}+...+4^{198}+4^{199}\)
\(=\left(4^{10}+4^{11}\right)+...+\left(4^{198}+4^{199}\right)\)
\(=4^{10}\left(1+4\right)+...+4^{198}\left(1+4\right)\)
\(=4^{10}\cdot5+...+4^{198}\cdot5\)
\(=5\cdot\left(4^{10}+...+4^{198}\right)⋮5\)
Vậy M là bội của 5