\(=lim\frac{\left(2+\frac{1}{n}\right)\left(1+\frac{n}{3}\right)\left(n-\frac{11}{n}\right)}{\left(1+\frac{1}{n}\right)\left(1+\frac{2}{n}\right)\left(1-\frac{5}{n}\right)}=\frac{\infty}{1}=+\infty\)
\(=lim\frac{\left(2+\frac{1}{n}\right)\left(1+\frac{n}{3}\right)\left(n-\frac{11}{n}\right)}{\left(1+\frac{1}{n}\right)\left(1+\frac{2}{n}\right)\left(1-\frac{5}{n}\right)}=\frac{\infty}{1}=+\infty\)
Tìm các giới hạn sau:
a) \(lim\left(4^n-3^n\right)\)
b) \(lim\left[\left(2^n+1\right)^2-4^n\right]\)
c) \(lim\left(\sqrt{2n^5-3n^2+11}-n^3\right)\)
d) \(lim\left(\sqrt{2n^2+1}-\sqrt{3n^2-1}\right)\)
e) \(lim\sqrt{n^2+3n\sqrt{n}+1}-n\)
a) \(lim\frac{\left(-2\right)^n+3^n}{\left(-2\right)^{n+1}+3^{n+1}}\)
b) \(lim\frac{\left(2n-1\right)\left(n+1\right)\left(3n+4\right)}{\left(5-6n\right)^3}\)
c) \(lim\left(\sqrt{n^2+5n+1}-\sqrt{n^2-2}\right)\)
d) \(lim\frac{5\cdot3^n-6^{n+1}}{4\cdot2^n+6^n}\)
e) \(lim\left(-2n^3-3n^2+5n-2020\right)\)
\(lim\left(\sqrt[3]{n-n^3}+\sqrt{n^2+3n}\right)\)
\(lim\left(\sqrt{n-2\sqrt{n}}-\sqrt{n+4}\right)\)
\(lim\left(\sqrt[3]{3n^2+n^3}-n\right)\)
\(lim\left(\sqrt[3]{n^3+6n}-\sqrt{n^2-4n}\right)\)
\(lim\frac{-3^{n+1}+4^{n+1}}{5.3^n+3.2^{2n-1}}\)
\(lim\left(\frac{3^{2n}-5^{n+1}+7^{n+1}}{3^{n+2}+5^n+2^{3n+2}}\right)\)
\(lim\left(\frac{6^{n+1}+3^{2n+5}}{3^{2n+3}-2^{2n-1}}\right)\)
17/lim\(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{\left(2n-1\right)\left(2n+1\right)}\right)\)
18/lim\(\frac{1+a+a^2+...+a^n}{1+b+b^2+...+b^n}\left(\left|a\right|< 1;\left|b\right|< 1\right)\)
19/lim\(\frac{1-2+3-4+...+\left(2n-1\right)-2n}{2n+1}\)
Tính giới hạn :
L = lim \(\dfrac{\left(n^2+2n\right)\left(2n^3+1\right)\left(4n+5\right)}{\left(n^4-3n-1\right)\left(3n^2-7\right)}\)
P2= lim\(\frac{\sqrt{n+1}}{\sqrt{n}+1}\)
M1= lim\(\frac{1+2+3+...+n}{^{ }n^2+2}\)
A5= lim\(\frac{\left(4-2n\right)^3\left(7n^2+1\right)^5}{\left(n^4+n^3-1\right)^2\left(4-5^5\right)}\)
Tìm các giới hạn sau:
a) \(lim\left(\sqrt{4n+1}-2\sqrt{n}\right)\)
b) \(lim\left(\sqrt{n^2+2n}-\sqrt{n^2-2n}-n\right)\)
c) \(lim\left(\sqrt{9^n-3^n}-4^n\right)\)
d) \(lim\left(3n^3+2n^2+n\right)\)
\(lim\sqrt[3]{n^2+n^3}+n.\) B))lim\(\frac{n^2+2\sqrt{n}+3}{2n^2+n-\sqrt{n}}\)
C))\(\frac{2n\sqrt{n}+3}{n^2+n+1}\) Đ)) lim \(\frac{\left(3+\sqrt{n}\right)\left(2n\sqrt{n}\right)}{\left(n+1\right)\left(n+2\right)}\)
tìm \(lim\dfrac{\left(2n\sqrt{n}+1\right)\left(\sqrt{n}+3\right)}{\left(n+1\right)\left(n+2\right)}\)