Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
1, sqrt{left(2+sqrt{5}right)^2}-sqrt{left(2-sqrt{5}right)}^2
2, sqrt{left(sqrt{3+1}right)^2+sqrt{left(1-sqrt{3}right)^2}}
3, sqrt{left(sqrt{2}+1right)^2}-sqrt{left(1-sqrt{2}right)^2}
4, sqrt{left(sqrt{3}+2right)^2}-sqrt{left(sqrt{3}-2right)^2}
5, sqrt{4-2sqrt{3}}+sqrt{4+2sqrt{3}}
6, sqrt{4+2sqrt{3}-sqrt{4-2sqrt{3}}}
Đọc tiếp
1, \(\sqrt{\left(2+\sqrt{5}\right)^2}-\sqrt{\left(2-\sqrt{5}\right)}^2\)
2, \(\sqrt{\left(\sqrt{3+1}\right)^2+\sqrt{\left(1-\sqrt{3}\right)^2}}\)
3, \(\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(1-\sqrt{2}\right)^2}\)
4, \(\sqrt{\left(\sqrt{3}+2\right)^2}-\sqrt{\left(\sqrt{3}-2\right)^2}\)
5, \(\sqrt{4-2\sqrt{3}}+\sqrt{4+2\sqrt{3}}\)
6, \(\sqrt{4+2\sqrt{3}-\sqrt{4-2\sqrt{3}}}\)
Tính:A2sqrt{left(-3right)^6}+2sqrt{left(-2right)^4}-4sqrt{left(-2right)^6}Bsqrt{left(sqrt{2}-2right)^2}+sqrt{left(sqrt{2}-3right)^2}Csqrt{left(3-sqrt{3}right)^2}-sqrt{left(1+sqrt{3}right)^2}Dsqrt{left(5+sqrt{6}right)^2}-sqrt{left(sqrt{6}-5right)^2}Esqrt{17^2-8^2}-sqrt{3^2+4^2}
Đọc tiếp
Tính:
\(A=2\sqrt{\left(-3\right)^6}+2\sqrt{\left(-2\right)^4}-4\sqrt{\left(-2\right)^6}\)
\(B=\sqrt{\left(\sqrt{2}-2\right)^2}+\sqrt{\left(\sqrt{2}-3\right)^2}\)
\(C=\sqrt{\left(3-\sqrt{3}\right)^2}-\sqrt{\left(1+\sqrt{3}\right)^2}\)
\(D=\sqrt{\left(5+\sqrt{6}\right)^2}-\sqrt{\left(\sqrt{6}-5\right)^2}\)
\(E=\sqrt{17^2-8^2}-\sqrt{3^2+4^2}\)
Rút gọn các biểu thứcM sqrt{left(3a-1right)^2}+2a-3 với a gedfrac{1}{3}N sqrt{left(4-aright)^2}-a+5 với a 4I sqrt{left(3-2aright)^2}+2-7 với a dfrac{3}{2}K dfrac{a^2-9}{4}sqrt{dfrac{4}{left(a-2right)^2}} với a 3
Đọc tiếp
Rút gọn các biểu thức
M = \(\sqrt{\left(3a-1\right)^2}+2a-3\) với a \(\ge\dfrac{1}{3}\)
N = \(\sqrt{\left(4-a\right)^2}-a+5\) với a > 4
I = \(\sqrt{\left(3-2a\right)^2}+2-7\) với a < \(\dfrac{3}{2}\)
K = \(\dfrac{a^2-9}{4}\sqrt{\dfrac{4}{\left(a-2\right)^2}}\) với a < 3
Tính:
\(A=\sqrt{20}-2\sqrt{45}+3\sqrt{18}+\sqrt{72}\)
\(B=4\sqrt{\left(\sqrt{3}-1\right)^2}+2\sqrt{12}+4\sqrt{\dfrac{1}{2}}\)
\(C=\left(3+\dfrac{3-\sqrt{3}}{\sqrt{3}-1}\right)\left(3-\dfrac{3+\sqrt{3}}{1+\sqrt{3}}\right)\)
\(D=\dfrac{1}{2+\sqrt{3}}+\dfrac{1}{2-\sqrt{3}}\)
Rút gọn:
A dfrac{4+sqrt{7}}{3sqrt{2}+sqrt{4+sqrt{7}}}+dfrac{4-sqrt{7}}{3sqrt{2}-sqrt{4-sqrt{7}}}
B dfrac{3sqrt{2}+sqrt{11}}{sqrt{2}+sqrt{6+sqrt{11}}}+dfrac{3sqrt{2}-sqrt{11}}{sqrt{2}-sqrt{6-sqrt{11}}}+18
C dfrac{1}{sqrt{3}+sqrt{5}}+dfrac{1}{sqrt{5}+sqrt{7}}+...+dfrac{1}{sqrt{2n+1}+sqrt{2n+3}}với n thuộc N*
D left(sqrt{3}+1right)left(sqrt{5}-1right)left(sqrt{15}-1right)left(7-2sqrt{3}+sqrt{5}right)
Edfrac{left(4+sqrt{3}right)}{sqrt[]{1}+sqrt{3}}+dfrac{left(8+sqrt{15}right)}{sqrt{3}+sqrt...
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Rút gọn:
A = \(\dfrac{4+\sqrt{7}}{3\sqrt{2}+\sqrt{4+\sqrt{7}}}+\dfrac{4-\sqrt{7}}{3\sqrt{2}-\sqrt{4-\sqrt{7}}}\)
B = \(\dfrac{3\sqrt{2}+\sqrt{11}}{\sqrt{2}+\sqrt{6+\sqrt{11}}}+\dfrac{3\sqrt{2}-\sqrt{11}}{\sqrt{2}-\sqrt{6-\sqrt{11}}}+18\)
C = \(\dfrac{1}{\sqrt{3}+\sqrt{5}}+\dfrac{1}{\sqrt{5}+\sqrt{7}}+...+\dfrac{1}{\sqrt{2n+1}+\sqrt{2n+3}}\)với n thuộc N*
D = \(\left(\sqrt{3}+1\right)\left(\sqrt{5}-1\right)\left(\sqrt{15}-1\right)\left(7-2\sqrt{3}+\sqrt{5}\right)\)
E=\(\dfrac{\left(4+\sqrt{3}\right)}{\sqrt[]{1}+\sqrt{3}}+\dfrac{\left(8+\sqrt{15}\right)}{\sqrt{3}+\sqrt{5}}+...+\dfrac{2k+\sqrt{k^2-1}}{\sqrt{k-1}+\sqrt{k+1}}+...+\dfrac{240+\sqrt{14399}}{\sqrt{119}+\sqrt{121}}\)
F = \(\left(\dfrac{2a+1}{a\sqrt{a}-1}-\dfrac{\sqrt{a}}{a+\sqrt{a}+1}\right)\left(\dfrac{1+a\sqrt{a}}{1+\sqrt{a}}-\sqrt{a}\right)\) với a >= 0 và a khác 1
Giúp mình 6 câu này với ạ, tối nay 7h là mình phải nộp cho thầy của mình rồi, mong các bạn giúp đỡ. 3
1,sqrt{left(2+sqrt{5}right)^2-sqrt{left(2-sqrt{5}right)}^2}
2,sqrt{left(2+sqrt{1}right)^2-sqrt{left(1-sqrt{2}right)}^2}
3, sqrt{left(sqrt{3+1}right)^2+sqrt{left(1-sqrt{3}right)}^2}
4, sqrt{left(sqrt{3}+2right)}^2-sqrt{left(sqrt{3}-2right)}^2
5,sqrt{4-2sqrt{3}}+sqrt{4+2sqrt{3}}
6, sqrt{4+2sqrt{3}-sqrt{4-2sqrt{3}}}
Đọc tiếp
Giúp mình 6 câu này với ạ, tối nay 7h là mình phải nộp cho thầy của mình rồi, mong các bạn giúp đỡ. <3
1,\(\sqrt{\left(2+\sqrt{5}\right)^2-\sqrt{\left(2-\sqrt{5}\right)}^2}\)
2,\(\sqrt{\left(2+\sqrt{1}\right)^2-\sqrt{\left(1-\sqrt{2}\right)}^2}\)
3, \(\sqrt{\left(\sqrt{3+1}\right)^2+\sqrt{\left(1-\sqrt{3}\right)}^2}\)
4, \(\sqrt{\left(\sqrt{3}+2\right)}^2-\sqrt{\left(\sqrt{3}-2\right)}^2\)
5,\(\sqrt{4-2\sqrt{3}}+\sqrt{4+2\sqrt{3}}\)
6, \(\sqrt{4+2\sqrt{3}-\sqrt{4-2\sqrt{3}}}\)
Rút gọn
1, 3sqrt{3}.left(3+2sqrt{6}-sqrt{33}right)
2, sqrt{2}.left(sqrt{8}-sqrt{32}+3sqrt{18}right)
3, left(2sqrt{28}-3sqrt{7}+5sqrt{63}right).sqrt{112}
4, left(5sqrt{6}-4sqrt{10}+7sqrt{30}right):sqrt{2}
5, left(5sqrt{3}+3sqrt{5}right):sqrt{15}
6, left(1+sqrt{3}-sqrt{2}right).left(1+sqrt{3}+sqrt{2}right)
7, left(4sqrt{27}-2sqrt{48}-5sqrt{75}right):2sqrt{3}
Các bạn ơi ! giúp mik với đi !!!
Đọc tiếp
Rút gọn
1, \(3\sqrt{3}.\left(3+2\sqrt{6}-\sqrt{33}\right)\)
2, \(\sqrt{2}.\left(\sqrt{8}-\sqrt{32}+3\sqrt{18}\right)\)
3, \(\left(2\sqrt{28}-3\sqrt{7}+5\sqrt{63}\right).\sqrt{112}\)
4, \(\left(5\sqrt{6}-4\sqrt{10}+7\sqrt{30}\right):\sqrt{2}\)
5, \(\left(5\sqrt{3}+3\sqrt{5}\right):\sqrt{15}\)
6, \(\left(1+\sqrt{3}-\sqrt{2}\right).\left(1+\sqrt{3}+\sqrt{2}\right)\)
7, \(\left(4\sqrt{27}-2\sqrt{48}-5\sqrt{75}\right):2\sqrt{3}\)
Các bạn ơi ! giúp mik với đi !!!
Tìm x
a)\(\sqrt{x-1}=2\left(x\ge1\right)\)
b)\(\sqrt{3-x}=4\left(x\le3\right)\)
c)\(2.\sqrt{3-2x}=\dfrac{1}{2}\left(x\le\dfrac{3}{2}\right)\)
d)\(4-\sqrt{x-1}=\dfrac{1}{2}\left(x\ge1\right)\)
e)\(\sqrt{x-1}-3=1\)
f)\(\dfrac{1}{2}-2.\sqrt{x+2}=\dfrac{1}{4}\)
Tính
A = \(\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{\left(1+\sqrt{3}\right)^2}\)
B = \(\sqrt{\left(4-\sqrt{5}\right)^2}-\sqrt{\left(2-\sqrt{5}\right)^2}\)
C = \(\sqrt{\left(1-\sqrt{5}\right)^2}-\sqrt{\left(2-\sqrt{5}\right)^2}\)