Question

1, \(\sqrt{\left(2+\sqrt{5}\right)^2}-\sqrt{\left(2-\sqrt{5}\right)}^2\)

2, \(\sqrt{\left(\sqrt{3+1}\right)^2+\sqrt{\left(1-\sqrt{3}\right)^2}}\)

3, \(\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(1-\sqrt{2}\right)^2}\)

4, \(\sqrt{\left(\sqrt{3}+2\right)^2}-\sqrt{\left(\sqrt{3}-2\right)^2}\)

5, \(\sqrt{4-2\sqrt{3}}+\sqrt{4+2\sqrt{3}}\)

6, \(\sqrt{4+2\sqrt{3}-\sqrt{4-2\sqrt{3}}}\)

Answer 1

1/ \(=2+\sqrt{5}-\left|2-\sqrt{5}\right|=2+\sqrt{5}-\sqrt{5}+2=4\)

2/ bạn coi lại đề

3/ \(=\sqrt{2}+1-\left|1-\sqrt{2}\right|=\sqrt{2}+1-\sqrt{2}+1=2\)

4/ \(=\sqrt{3}+2-\left|\sqrt{3}-2\right|=\sqrt{3}+2-2+\sqrt{3}=2\sqrt{3}\)

5/ \(=\sqrt{\left(\sqrt{3}-1\right)^2}+\sqrt{\left(\sqrt{3}+1\right)^2}=\sqrt{3}-1+\sqrt{3}+1=2\sqrt{3}\)

6/ \(=\sqrt{\left(\sqrt{3}+1\right)^2}-\sqrt{\left(\sqrt{3}-1\right)^2}=\sqrt{3}+1-\sqrt{3}+1=2\)

Answer 2

Các bạn giúp mình với, tối nay mình nộp rồi.

Câu 6 sửa lại đề giúp mình như này nhé:

\(\sqrt{4+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}\)