1. Rút gọn
P=\(2\sqrt{1+\frac{1}{4}\left(\sqrt{\frac{1}{x}}-\sqrt{x}\right)^2}:\left[\sqrt{1+\frac{1}{4}\left(\sqrt{\frac{1}{x}}-\sqrt{x}\right)^2}-\frac{1}{2}\left(\sqrt{\frac{1}{x}}-\sqrt{x}\right)^2\right]\)
Rút gọn A = \(\left(\frac{x+2\sqrt{x}+4}{x\sqrt{x}-8}+\frac{x+2\sqrt{x}+1}{x-1}\right) :\left(3+\frac{1}{\sqrt{x}-2}+\frac{2}{\sqrt{x}+1}\right)\)
a, Rút gọn A b , Tìm x thỏa mãn A > 1 c,Tính A với \(x=\frac{\sqrt{4+\sqrt{3}}+\sqrt{4-\sqrt{3}}}{\sqrt{4+\sqrt{13}}}+\sqrt{27-10\sqrt{2}}\)\(A=\frac{\sqrt{x}+1}{3\left(\sqrt{x}-1\right)}\)
Gpt: a) \(\sqrt[4]{3\left(x+5\right)}-\sqrt[4]{11-x}=\sqrt[4]{13+x}-\sqrt[4]{3\left(3-x\right)}\)
b) \(\frac{1+2\sqrt{x}-x\sqrt{x}}{3-x-\sqrt{2-x}}=2\left(\frac{1+x\sqrt{x}}{1+x}\right)\) c) \(\sqrt{x+1}+\frac{4\left(\sqrt{x+1}+\sqrt{x-2}\right)}{3\left(\sqrt{x-2}+1\right)^2}=3\)
d) \(\sqrt{\frac{x-2}{x+1}}+\frac{x+2}{\left(\sqrt{x+2}+\sqrt{x-2}\right)^2}=1\) e) \(2x+1+x\sqrt{x^2+2}+\left(x+1\right)\sqrt{x^2+2x+2}=0\)
f) \(\sqrt{2x+3}\cdot\sqrt[3]{x+5}=x^2+x-6\)
Rút gọn biểu thức:
\(Q=\left(\frac{x-\sqrt{x}+7}{x-4}+\frac{1}{\sqrt{x}-2}\right):\left(\frac{\sqrt{x}+2}{\sqrt{x}-2}-\frac{\sqrt{x}-2}{\sqrt{x}+2}-\frac{2\sqrt{x}}{x-4}\right)\)
\(A=\left(\frac{3\sqrt{x}}{\sqrt{x}+2}-\frac{\sqrt{x}}{\sqrt{x}-2}-\frac{8\sqrt{x}}{4-x}\right):\left(2-\frac{2\sqrt{x}+3}{\sqrt{x}+2}\right)\)
a) RG A
b) Tìm GTNN của A với x > 4
1.Chmr rằng nếu: a,b >0 thì \(\sqrt{a}+\sqrt{b}\le\sqrt{\frac{a^2}{b}}+\sqrt{\frac{b^2}{a}}\)
2. Rg biểu thức:
\(A=\frac{\sqrt{x-\sqrt{4\left(x-1\right)}}+\sqrt{x+\sqrt{4\left(x-1\right)}}}{\sqrt{x^2-4\left(x-1\right)}}.\left(1-\frac{1}{x-1}\right)\)
P=\(\left(\frac{4\sqrt{x}}{2-\sqrt{x}}-\frac{8x}{4-x}\right):\left(\frac{\sqrt{x}-4}{x+2\sqrt{x}}+\frac{1}{\sqrt{x}}\right)\)
Rút gọn
Tìm điều kiện x để các biểu thức sau \(a)\frac{x}{x^2-4}+\sqrt{x-2}\\ b)\frac{\sqrt{x}}{\left|x\right|-1}\\ c)\frac{2}{\left|x\right|+4}+\sqrt{x^2-4}\\ d)\frac{1}{\sqrt{x-2\sqrt{x-1}}}\\ e)\sqrt{x^2-2x}+3\sqrt{4-x^2}\)
\(\left(\frac{\sqrt{x}-4}{x-2\sqrt{x}}-\frac{3}{2-\sqrt{x}}\right):\left(\frac{\sqrt{x}+2}{\sqrt{x}}-\frac{\sqrt{x}}{\sqrt{x}-2}\right)\)
rút gọn