Giải hpt sau:
a) \(\left\{{}\begin{matrix}\sqrt{5}x+\left(1-\sqrt{3}\right)y=1\\\left(1-\sqrt{3}\right)x+\sqrt{5}y=1\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\frac{3x}{x+1}-\frac{2y}{y+4}=4\\\frac{2x}{x+1}-\frac{5y}{y+4}=5\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}3x-2\left|y\right|=9\\2x+3\left|y\right|=1\end{matrix}\right.\)
d) \(\left\{{}\begin{matrix}\frac{2}{2x-y}+\frac{3}{x-2y}=\frac{1}{2}\\\frac{2}{2x-y}-\frac{1}{x-2y}=\frac{1}{18}\end{matrix}\right.\)
Giải hệ phương trình
1.\(\left\{{}\begin{matrix}x^2=3y-2\\y^2=3x-2\end{matrix}\right.\)
2.\(\left\{{}\begin{matrix}2x+\frac{1}{y}=\frac{3}{x}\\2y+\frac{1}{x}=\frac{3}{y}\end{matrix}\right.\)
3.\(\left\{{}\begin{matrix}3y=\frac{y^2+2}{x^2}\\3x=\frac{x^2+2}{y^2}\end{matrix}\right.\)
4.\(\left\{{}\begin{matrix}x^3=3y+2\\y^3=3x+2\end{matrix}\right.\)
PLEASE HELP ME
Giải hệ phương trình :
a, \(\left\{{}\begin{matrix}2x-\frac{1}{y}=2y-\frac{1}{x}\\2\left(2x^2+y^2\right)+4\left(x-y\right)=7xy-8\end{matrix}\right.\)
b, \(\left\{{}\begin{matrix}2x^3-5y=2y^3-5x\\\frac{3y}{x^2+y+1}+\frac{5x}{\left(y+1\right)^2+x}=x-y+2\end{matrix}\right.\)
(Mong mọi người giúp đỡ! Tick cho mọi người nha !)
\(\left\{{}\begin{matrix}\frac{1}{x}+\frac{3}{y-2}=4\\\frac{4}{x}+\frac{1}{y-2}=1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\frac{2x+3}{x+1}+\frac{4}{\sqrt{y}-2}=4\\\frac{5}{x+1}-\frac{2}{\sqrt{y}-2}=4\end{matrix}\right.\)
giải hpt:
\(\left\{{}\begin{matrix}\frac{5}{\sqrt{x-1}}-3\left|y+1\right|=-4\\\frac{2}{\sqrt{x-1}}+\left|y+1\right|=5\end{matrix}\right.\)
Giải hộ mình câu này với ạ
\(\left\{{}\begin{matrix}\frac{2}{x-1}\frac{1}{y+1}=7\\\frac{5}{x-1}-\frac{2}{y-1}=4\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\frac{2}{x-2}+3\sqrt{y+1}=4\\\frac{4}{x-2}-\sqrt{y+1}=1\end{matrix}\right.\) tìm đk rồi giải hpt hộ mình nha