\(=\left(15\cdot10\sqrt{2}-3\cdot15\sqrt{2}+2\cdot5\sqrt{2}\right):10\\ =\left(150\sqrt{2}-45\sqrt{2}+10\sqrt{2}\right):10\\ =115\sqrt{2}:10=\dfrac{23\sqrt{2}}{2}\)
Tính giá trị các biểu thức:
a.\(\left(7\sqrt{48}+3\sqrt{27}-2\sqrt{12}\right)\sqrt{3}\)
b.\(\left(12\sqrt{50}-8\sqrt{200}+7\sqrt{450}\right):\sqrt{10}\)
c.\(\left(2\sqrt{6}-4\sqrt{3}+5\sqrt{2}-\dfrac{1}{4}\sqrt{8}\right)3\sqrt{6}\)
d.\(3\sqrt{15\sqrt{50}}+5\sqrt{24\sqrt{8}}-4\sqrt{12\sqrt{32}}\)
rút gọn
a) \(\sqrt{\left(2-\sqrt{3}\right)^2}\) + \(\sqrt{4-2\sqrt{3}}\)
b) \(\sqrt{15-6\sqrt{5}}\) + \(\sqrt{33-12\sqrt{6}}\)
c) \(\left(15\sqrt{200}-3\sqrt{450}+2\sqrt{50}\right):\sqrt{10}\)
a) \(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right)\sqrt{7}+7\sqrt{8}\)
b) \(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):10\)
c) \(\left(\sqrt{8}-3\sqrt{2}+\sqrt{10}\right)\left(\sqrt{2}-3\sqrt{0,4}\right)\)
thực hiện các phép tính trên
1,Rút gọn biểu thức sau
a,(\(\sqrt{3}-\sqrt{2}+1\) ).(\(\sqrt{3}-1\) )
b,(0,2\(\sqrt{\left(-10\right)^2.3}\) +2\(\sqrt{\left(\sqrt{3}-\sqrt{5}\right)^2}\)
c,(\(\sqrt{28}-2\sqrt{14}+\sqrt{7}\) ).\(\sqrt{7}+7\sqrt{8}\)
d,(\(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\) ):\(\sqrt{10}\)
Thực hiện phép tính :
1, \(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right).\sqrt{7}+7\sqrt{8}\)
2, \(\left(\sqrt{8}-3\sqrt{2}+\sqrt{10}\right).\left(\sqrt{2}-3\sqrt{0,4}\right)\)
3, \(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)
4, \(\sqrt{6+2\sqrt{5}}+\sqrt{6-2\sqrt{5}}\)
5. \(\sqrt{11+6\sqrt{2}}-\sqrt{11-6\sqrt{2}}\)
Mọi người ơi giúp em bài này với
Ai đã từng học lớp 9 rồi thì giúp em pls
Tính:
1)a)\(2\sqrt{40.\sqrt{12}}-2\sqrt{\sqrt{75}}-3\sqrt{548}\)
b)\(\left(\sqrt{12}+\sqrt{75}+\sqrt{27}\right):\sqrt{15}\)
d)\(\left(12\sqrt{50}-8\sqrt{200}+7\sqrt{450}\right):\sqrt{10}\)
e) (\(\sqrt{\dfrac{1}{7}}-\sqrt[]{\dfrac{16}{7}}+\sqrt[]{\dfrac{9}{7}}\)):\(\sqrt{7}\)
2)
a)A=\(\sqrt{3+\sqrt{5+2\sqrt{3}}}.\sqrt{3-\sqrt[]{5+2\sqrt[]{3}}}\)
b) B=\(\sqrt{4+\sqrt{8}}\) . \(\sqrt{2+\sqrt{2+\sqrt{2}}}\) .\(\sqrt{2-\sqrt{2+\sqrt{2}}}\)
Tính (rút gọn)
a) \(\left(\sqrt{3+\sqrt{5}}\right)\left(\sqrt{10}+\sqrt{2}\right)\left(3-\sqrt{5}\right)\)
b) \(\left(4+\sqrt{15}\right)\left(\sqrt{10-\sqrt{6}}\right)\sqrt{4-}\sqrt{15}\)
c) \(\left(\sqrt{6}+\sqrt{2}\right)\left(\sqrt{3}-2\right)\sqrt{\sqrt{3+2}}\)
d) \(\left(2\sqrt{4+\sqrt{6-2\sqrt{5}}}\right)\left(\sqrt{10}-\sqrt{2}\right)\)
f)\(\sqrt{\dfrac{3-\sqrt{5}}{2-\sqrt{3}}}\)
g)\(\dfrac{\sqrt{2+\sqrt{3}}}{3+\sqrt{3}}\)
h)\(\sqrt{4-\sqrt{15}}+\sqrt{4+\sqrt{15}}-2\sqrt{3-\sqrt{5}}\)
Tính: a. \(\left(3\sqrt{2}+\sqrt{6}\right)\cdot\left(6-3\sqrt{3}\right)\)
b. \(\left(4+\sqrt{15}\right)\cdot\left(\sqrt{10}-\sqrt{6}\right)\cdot\sqrt{4-\sqrt{15}}\)
c. \(\left(3-\sqrt{5}\right)\cdot\left(10-\sqrt{2}\right)\cdot\sqrt{3+\sqrt{5}}\)
Tính :
a) \(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
b)\(\sqrt{3-\sqrt{5}}\left(\sqrt{10}-\sqrt{2}\right)\left(3+\sqrt{5}\right)\)
c) \(\dfrac{\sqrt{\sqrt{5}+2}+\sqrt{\sqrt{5}-2}}{\sqrt{\sqrt{5}+1}}-\sqrt{3-2\sqrt{2}}\)
