Ôn tập toán 6
Các câu hỏi tương tự
Giúp với câu này khó quá :\(\left(1-\frac{2}{2.3}\right).\left(1-\frac{2}{3.4}\right)...\left(1-\frac{2}{99.100}\right)\)có cả lời giải nhé
Tìm x thuộc z:
\(\frac{1.2+2.3+3.4+...+99.100}{x+\left(x^2+1\right)+\left(x^2+2\right)+...+\left(x^2+99\right)}\)=\(50^{116}_{131}\)
Tính nhanh:
A = \(\left(\frac{1}{4}-1\right).\left(\frac{1}{9}-1\right).\left(\frac{1}{16}-1\right).\left(\frac{1}{25}-1\right).....\left(\frac{1}{121}-1\right)\)
HELP ME
Tính:
\(M=\frac{\left(1+17\right)\left(1+\frac{17}{2}\right)\left(1+\frac{17}{3}\right)........\left(1+\frac{17}{19}\right)}{\left(1+19\right)\left(1+\frac{19}{2}\right)\left(1+\frac{19}{3}\right)........\left(1+\frac{19}{17}\right)}\)
Cho A=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{2013^2}-1\right)..\left(\frac{1}{2014^2}-1\right)\&B=\frac{1}{2}\) so sánh A và B
Tính :
a ) \(\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right)...\left(\frac{1}{99}+1\right)\)
b )\(\left(\frac{1}{2}-1\right).\left(\frac{1}{3}-1\right)...\left(\frac{1}{100}-1\right)\)
c ) \(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{899}{30^2}\)
Câu 1: Tính
a) A=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).....\left(\frac{1}{98^2}-1\right).\left(\frac{1}{99^2}-1\right)\)
b) B=\(\frac{1}{2}:\left(-1\frac{1}{2}\right):1\frac{1}{3}:\left(-1\frac{1}{4}\right):1\frac{1}{5}:\left(-1\frac{1}{6}\right):...:\left(-1\frac{1}{100}\right)\)
c) C=\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^4}\)
Tính:
\(\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right).\left(\frac{1}{5^2}-1\right)...\left(\frac{1}{50^2}-1\right)\)
\(A=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+...+\frac{1}{16}\left(1+2+..+16\right)\)