a) x2(5x3 – x - \(\dfrac{1}{2}\) )= x2. 5x3 + x2 . (-x) + x2 . (-\(\dfrac{1}{2}\))
= 5x5 – x3 – \(\dfrac{1}{2}\)x2
b) (3xy – x2 + y)\(\dfrac{2}{3}\)x2y = \(\dfrac{2}{3}\)x2y . 3xy + \(\dfrac{2}{3}\)x2y . (- x2) + \(\dfrac{2}{3}\)x2y . y
= 2x3y2 – \(\dfrac{2}{3}\)x4y + \(\dfrac{2}{3}\)x2y2
c) (4x3– 5xy + 2x)(- \(\dfrac{1}{2}\)xy) = - \(\dfrac{1}{2}\)xy . 4x3 + (- \(\dfrac{1}{2}\)xy) . (-5xy) + (- \(\dfrac{1}{2}\)xy) . 2x
= -2x4y + \(\dfrac{5}{2}\)x2y2 - x2y.
a) x2 (5x3 - x - \(\dfrac{1}{2}\))
= 5x5 - x3 - \(\dfrac{1}{2}\)x2
b) (3xy - x2 + y) \(\dfrac{2}{3}\)x2y
= 2x3y2 - \(\dfrac{2}{3}\)x4y + \(\dfrac{2}{3}\)x2y2
c) (4x3 - 5xy +2x) (-\(\dfrac{1}{2}\)xy)
= -2x4y + \(\dfrac{5}{2}\)x2y2 - x2y
x2 ( 5x3- x - \(\dfrac{1}{2}\) )
=5x5-x3-\(\dfrac{1}{2}\)x2
( 3xy -x2 + y) . \(\dfrac{2}{3}\)x2y
= 2x3y2 - \(\dfrac{2}{3}\)x4y + \(\dfrac{2}{3}\)x2y2
( 4x3- 5xy + 2x ) . ( -\(\dfrac{1}{2}\)xy )
= -2x4y + \(\dfrac{5}{2}\)x2y2 - x2y
a) x2(5x3 – x - 12 )= x2. 5x3 + x2 . (-x) + x2 . (-12)
= 5x5 – x3 – 12x2
b) (3xy – x2 + y)23x2y = 23x2y . 3xy + 23x2y . (- x2) + 23x2y . y
= 2x3y2 – 23x4y + 23x2y2
c) (4x3– 5xy + 2x)(- 12xy) = - 12xy . 4x3 + (- 12xy) . (-5xy) + (- 12xy) . 2x
= -2x4y + 52x2y2 - x2y.
a) x2(5x3 – x - 12 )= x2. 5x3 + x2 . (-x) + x2 . (-12)
= 5x5 – x3 – 12x2
b) (3xy – x2 + y)23x2y = 23x2y . 3xy + 23x2y . (- x2) + 23x2y . y
= 2x3y2 – 23x4y + 23x2y2
c) (4x3– 5xy + 2x)(- 12xy) = - 12xy . 4x3 + (- 12xy) . (-5xy) + (- 12xy) . 2x
= -2x4y + 52x2y2 - x2y.
a) x2(5x3 – x - 1 2 )= x2. 5x3 + x2 . (-x) + x2 . (- 1 2 ) = 5x5 – x3 – 1 2 x2 b) (3xy – x2 + y) 2 3 x2y = 2 3 x2y . 3xy + 2 3 x2y . (- x2) + 2 3 x2y . y = 2x3y2 – 2 3 x4y + 2 3 x2y2 c) (4x3– 5xy + 2x)(- 1 2 xy) = - 1 2 xy . 4x3 + (- 1 2 xy) . (-5xy) + (- 1 2 xy) . 2x = -2x4y + 5 2 x2y2 - x2y.
a) x2(5x3 – x - 1212)
= 5x5 – x3 – 2323x2y = 2323x2y . (- x2) + 2323x4y + 1212xy) = - 1212xy) . (-5xy) + (- 5252x2y2 - x2y.
_chúc bn lm bt tốt nha_