PTHH: \(4FeS_2+11O_2\underrightarrow{to}2Fe_2O_3+8SO_2\\ 0,2mol:0,55mol\leftarrow0,1mol:0,4mol\\ 100000mol:275000mol\rightarrow50000mol:200000mol\)
a. \(n_{Fe_2O_3}=\dfrac{16}{160}=0,1\left(mol\right)\)
\(m_{FeS_2}=0,2.120=24\left(g\right)\)
b. \(n_{FeS_2}=\dfrac{12000000}{120}=100000\left(mol\right)\)
\(m_{Fe_2O_3}=50000.160=8000000\left(g\right)=8\left(Tan\right)\)