\(n_{H_2}=\frac{3,36}{22,4}=0,15\left(mol\right)\)
\(PTHH:2Al+6HX\rightarrow2AlX_3+3H_2\)
(mol)____0,1____0,3_____0,1______0,15__
\(m_{Al}=0,1.27=2,7\left(g\right)\)
\(C_{M_{HX}}=\frac{0,3}{0,2}=1,5\left(M\right)\)
\(BTKL:\Rightarrow m_{HX}=5,1+0,15.2-2,7=2,7\left(g\right)\)
\(\Rightarrow M_{HX}=1+M_X=\frac{2,7}{0,3}=9\Leftrightarrow M_X=8\)
\(\rightarrow\) Không có nguyên tố X phù hợp